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自动化翻译岗位职责篇一
the operational amplifier one problem with electronic devices corresponding to the generalized amplifier is that the gains, au or ai, depend upon internal properties of the two-port system(β, µ, ri, ro, etc.).this makes design difficult since these parameters usually vary from device to device, as well as with operational amplifier, or op-amp,is designed to minimize this dependence and to maximize the ease of op-amp is an integrated circuit that has many component part such as resistors and transistors built into the this point we will make no attempt to describe these inner working.a totally general analysis of the op-amp is beyond the scope of some will instead study one example in detail, then present the two op-amp laws and show how they can be used for analysis in many practical circuit two principles allow one to design many circuits without a detailed understanding of the device , op-amps are quit useful for researchers in a variety of technical field who need to build simple amplifiers but do not want to design at the transistor the texts of electrical circuits and electronics they will also show how to build simple filter circuits using transistor amplifiers, which are the building blocks form which op-amp integrated circuits are constructed, will be symbol used for an idea op-amp is shown in three connections are shown: the positive and negative inputs, and the shown are other connections neceary to run the op-amp such as its attachments to power supplies and to ground latter connections are neceary to use the op-amp in a practical circuit but are not neceary when considering the ideal op-amp applications we study in this voltages at the two inputs and the output will be represented by the symbols, is measured with respect to ground ional amplifiers are differential this we mean that the output voltage with respect to ground is given by the expreion
= a(-)
(1-2a-1)where a is the gain of the op-amp and and the voltages at other words, the output voltage is a time the difference in potential between the two tegrated circuit technology allows constructions of many amplifier circuits on a single composite “chip” of semiconductor key to the succe of an operational amplifier is the “cascading” of number of transistor amplifiers to create a very large total is, the number a in ep.(1-2a-1)can be on the order of 100,000 or more.(for example, cascading of five transistor amplifiers, each with a gain of 10, would yield this value for a.)a second important factor is that these circuit can be built in such a way that the current flow into each of the inputs is very small.a third important design feature is that the output resistance of the operational amplifier()is very in turn means that the outpt of the device acts like an ideal voltage now can analyze the particular amplifier circuit given in fig.1-2a-2 using these , we note that the voltage at the positive input, =.various currents are defined in part b of the ng kvl around the outer loop in fig.1-2a-2band remembering that the output voltage, , is measured with respect to ground, we have
--=0
(1-2a-2)since the op-amp is constructed in such a way that no current flows into either the positive or negative input, = ng kcl at the negative input terminal then yields
= using ep.(1-2a-3)and setting,i we may use ohm’s law to find the voltage at the negative input, , nothing the aumed current direction and the fact that ground potential is zero volts:
= i so,and form ep.(1-2a-3)
=()
since we now have expreions for , eq.(1-2a-1)may be used to calculate the output voltage,gathering terms,(1-2a-4)
and finally,(1-2a-5a)this is the gain factor for the a is a very large number, large enough that a >>(), the denominator of this fraction is dominated by the a factor a, which is in both the numerator and denominator, then cancels out and the gain is given by the expreion
(1-2a-5b)this shows that if a is very large, then the gain of the circuit is independent of the exact value of a and can be controlled by the choice is one of the key features of op-amp design—the action of the circuit on signals depends only upon the the external elements which can be easily varied by the designer and which do not depend upon the detailed character of the op-amp that if a = 100,000 and()/=10, the price we have paid for this advantage is that we have used a device with a voltage gain of 100,000 to produce an amplifier with a gain of some sense, by using an op-amp we trade off “power” for “control”.a similar mathematical analysis can be made on any op-amp circuit, but this is cumbersome and there are some very useful shortcuts that involve application of the two laws of op-amps which we now present.1)the first law states that in normal op-amp circuit we may aume that the voltage difference between the input terminals is zero, that is
2)the second law states that is normal op-amp circuit both of the input currents may be aumed to be zero:
the first law is due to the large value of the intrinsic gain example, if the output of an op-amp is 1 v and a=100,000, then is such a small number that can often be ignored, and we second law comes from the construction of the circuitry inside the op-amp which is such that almost no current flows into either of the two inputs.第二部分:翻译
运算放大器
运算放大器像广义放大器这样的电子器件存在的一个问题就是它们的增益au或ai取决于双端口系统(m、b、ri、ro等)的内部特性。器件之间参数的分散性和温度漂移给设计工作增加了难度。设计运算放大器或op-amp的目的就是使它尽可能的减少对其内部参数的依赖性、最大程度地简化设计工作。运算放大器是一个集成电路,在它内部有许多电阻、晶体管等元件。就此而言,我们不再描述这些元件的内部工作原理。
运算放大器的全面综合分析超越了某些教科书的范围。在这里我们将详细研究一个例子,然后给出两个运算放大器定律并说明在许多实用电路中怎样使用这两个定律来进行分析。这两个定律可允许一个人在没有详细了解运算放大器物理特性的情况下设计各种电路。因此,运算放大器对于在不同技术领域中需要使用简单放大器而不是在晶体管级做设计的研究人员来说是非常有用的。在电路和电子学教科书中,也说明了如何用运算放大器建立简单的滤波电路。作为构建运算放大器集成电路的积木—晶体管,将在下篇课文中进行讨论。理想运算放大器的符号如图1-2a-1所示。图中只给出三个管脚:正输入、负输入和输出。让运算放大器正常运行所必需的其它一些管脚,诸如电源管脚、接零管脚等并未画出。在实际电路中使用运算放大器时,后者是必要的,但在本文中讨论理想的运算放大器的应用时则不必考虑后者。两个输入电压和输出电压用符号u +、u-和uo 表示。每一个电压均指的是相对于接零管脚的电位。运算放大器是差分装置。差分的意思是:相对于接零管脚的输出电压可由下式表示(1-2a-1)式中
= a(-)
(1-2a-1)a 是运算放大器的增益,u + 和 u=0。那么对负输入端利用基尔霍夫定律可得
=,利用等式(1-2a-2),并设 ==1,u0 =(r1 +r2)i(1-2a-3)根据电流参考方向和接零管脚电位为零伏特的事实,利用欧姆定律,可得负极输入电压uunit1 – 《a the operational amplifier》的翻译,我对专业英语的翻译有了很深的认识。以前总觉得翻译就是用正确的语法把特定的词语组织起来,表达流利就足够了,在前几段刚刚翻译的段落都是采用直译的手法,翻译出来的词句不但读不通而且逻辑不通,自动化专业英语翻译让我受益匪浅。翻译是跨语言、跨文化、跨社会的交际活动。
翻译是有灵魂的,语言是人与人交流的重要工具,翻译也是文化的交流。像纽马克说的,翻译是一门科学,艺术,技术也是一种品位。翻译不是精通一门外语,借助于词典和工具书就能为之的事,缺少对原语文化的深人研究很难保证翻译的水平和质量。翻译要熟悉两种语言,悟出语言所具有的无比威力,还要透过语言所传达的信息,了解其背后的文化和精神,从而体会到中西文化的差异。自动化专业英语的翻译更加是一门科学艺术。例如这句:
one problem with electronic devices corresponding to the generalized amplifier is that the gains, au or ai, depend upon internal properties of the two-port system(β, µ, ri, ro, etc.).----原文
翻译:运算放大器像广义放大器这样的电子器件存在的一个问题就是它们的增益au或ai取决于双端口系统(m、b、ri、ro等)的内部特性。像这句就不单单是注意语句颠倒和生词翻译的问题了,专业性的词two-port system(双端口系统)和gains翻译为 ”增益” 而不是字典的 ”获得,收获” 以及翻译技巧应用于上半句从tothe generalized amplifier 开始把 one problem 放后面。类似的还有
this is one of the key features of op-amp design—the action of the circuit on signals depends only upon the the external elements which can be easily varied by the designer and which do not depend upon the detailed character of the op-amp itself.—(原文)
这是运算放大器设计的重要特征之一----在信号作用下,电路的动作仅取决于能够容易被设计者改变的外部元件,而不取决于运算放大器本身的细节特性。(翻译)
其中,有运算放大器的简称op-amp 的翻译,词组 depend … upon … 取决于…,这句除了常见的颠倒还要注意各分句的主语以及后面接的谓语动词,要先捋清楚,把句子单独抽取出来翻译。
语言不仅仅是信息的载体,还是文化的载体。不同民族由于不同的生存环境,不同的认识世界的角度,往往形成各自独特的文化模式。科技文原文读者与原文作者一般具有共同的文化背景和科技文化基础,因此原文读者要想按作者所期望的那样,透过词汇的表面形式去理解原文的全部文化内涵和其中的科技文化信息,和译者根据自己的语言和科技文化基础来传达信息、表达感情,他所面对的则是难以理解甚至是更容易误解的文化材料,因此“翻译者必须是一个真正意义上文化人”。译者不仅应该精通原语和译人语这两种语言,而且应该通过各种信息渠道了解这两种语言所反映的文化和知识,谙熟它们的差异,才能找到契合点,最大限度地缩小原作和译者之间的距离,准确地捕捉原文中的文化信息,进行有效的传播。
要能翻译出好的作品,不是一朝一夕的事情,还需要经过大量艰苦的理论学习与实践,一个优秀的翻译工作者,不仅要有很大的词汇量和扎实的语言功底,还要博览群书,通观世界,关注国内外时事。而当前我们正刚开始接触专业英语翻译,首先要做的是学好各种翻译技能,切不可心浮气躁,急于求成。理论虽然枯燥,但理论是实践的指导,有了一定的理论基础才能找到合适的方法翻译并发现翻译中的问题。
在高度信息化和全球化的现代社会中,翻译的重要性得到了越来越多的体现。作为自动化专业的我们,做好自动化专业英语翻译是一项有趣并且有意义的任务。学好自动化专业知识,才能体会到自动化专业英语翻译的乐趣,才能有更好的基础和方法拓宽自己自动化专业知识的学习面。
自动化翻译岗位职责篇二
自动化工程师岗位职责
1、负责公司自动化仪表设备的日常维护、维修工作,确保各仪
表设备的稳定运行。
2、负责公司自动化仪表设备的年度检修工作。
3、负责公司自动化仪表设备硬件、软件的改造与更新工作。
4、根据生产工艺要求,修改自动控制系统组态软件的控制方案。
5、定期组织自动化人员进行安全、技能培训,努力提高自动化
操作人员安全、技术素质。
6、加强自动化仪表、设备的日常巡检工作。
7、协助采购部寻找合适的设备和零部件供应商。
8、确定电子和控制系统损件名称型号,并根据实际情况储备易
损部件。
9、有针对项目仪表设备、控制系统技术革新、改造提出合理化
建议的责任。
10、认真贯彻执行公司的各项规章制度。
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